If glucose and glucose-6-phosphate are both at 12.6 mm, what is the equilibrium concentration of phosphate (pi)?

Answer :

The correct answer is  212.77mM

The reaction between glucose and glucose-6-phosphate is given as :

Glucose + pi  → Glucose-6-phosphate + H₂O  

The equilibrium constant for this reaction (Keq) is 0.0047

The expression for equilibrium constant is given as :

Where all the concentration are

Given :  Concentration of Glucose 12.6mM

           Concentration of Glucose-6-phosphate = 12.6 mM

Asked : Concentration of phosphate (pi) = ?

Plugging above values in equilibrium constant expression :

By Cross multiplying  :

[pi] = 212.77 mM

The concentration of phosphate (pi) = 212.77mM .

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