The density of lead is 1.135×104 kg/m3. what is the mass of a rectangular ingot of lead with dimensions 2.00 cm × 2.00 cm × 0.850 dm?

              Mass =  385.9 g

Data Given:

                  Density =  1.135 × 10⁴ Kg/m³  =  11.35 g/cm³

                  Volume  =  2.0 cm × 2.0 cm × 0.850 dm

As (1 decimeter  =  10 Centimeter) So,

                  Volume  =  2.0 cm × 2.0 cm × 8.5 cm  =  34 cm³

Formula Used:

                       Density  =  Mass ÷ Volume

Solving for Mass,

                        Mass  =  Density × Volume

                        Mass  =  11.35 g/cm³ × 34 cm³

                        Mass =  385.9 g

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