Calculate the mean free path of air molecules at 3.50 * 10-13 atm and 300 k. (this pressure is readily attainable in the laboratory; see exercise 18.23.) as in example 1

The mean free path can be defined as the average distance between collisions for gas molecules. It can be calculated using the formula:

∧ = ---------(1)

Given :

T = 300 K

P = 3.50 * 10-13 atm = 3.55 * 10^-8 pascals

d = diameter of air molecules = 2* radius of air molecules

                                                 = 2* 2*10^-10 m = 4*10^-10 m

k = Boltzmann constant = 1.38 * 10^-23 J/K

Na = avogadro's number = 6.023 * 10^23

Substituting in equation(1) we get:

∧ = 1.38 *10^-23* 300/√2*π*(4*10^-10)²*3.55*10^-8

  = 1.641*10^5 m

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.