If 0.0987 g h2o hydrolyzes, what is the theoretical yield of h2? 2h2o → → 2h2 + o2

The theoretical yield is 0.0110 g H₂.

Moles of H₂O = 0.0987 g H₂O × (1 mol H₂O/18.02 g H₂O) = 0.005 477 mol H₂O

Moles of H₂ = 0.005 477 mol H₂O × (2 mol H₂/2 mol H₂O) = 0.005 477 mol H₂

Theoretical yield of H₂ = 0.005 477 mol H₂ × (2.016 g H₂/1 mol H₂)

= 0.0110 g H₂

Theoretical yield of is 0.01 grams.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.

To calculate the number of moles, we use the equation:

According to stoichiometry:

2 moles of water produces = 2 moles of hydrogen

Thus 0.005 moles of water produces = moles of hydrogen

Mass of produced =

Thus theoretical yield of is 0.01 grams.