Arate is equal to 0.0200 m/s. if [a] = 0.100 m and rate = k[a][b]2, what is the new rate if the concentration of [a] is increased to 0.200 m?

The new rate is 0.0400 mol·L⁻¹s⁻¹.

r = k[A][B]²

The reaction is first order in [A].

If you double [A], you double the rate.

The new rate is 2 × 0.0200 mol·L⁻¹s⁻¹ = 0.0400 mol·L⁻¹s⁻¹ .

you did not give any options thus this is the best answer i can give to you with this little information you have given

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the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .