Larisa pumps up a soccer ball until it has a gauge pressure of 61 kilopascals. the volume of the ball is 5.2 liters. the air temperature is 32°c, and the outside air is at standard pressure. how many moles of air are in the ball?

The total ball pressure is sum of gauge pressure and atmospheric pressure

We know that atmospheric pressure = 101.325 kPa

so the total ball pressure = 61 kPa + 101.325 kPa = 162.325 kPa

Now we will use ideal gas equation as

PV = nRT

P = pressure = 162.325 kPa

V = 5.2 L

R = gas constant = 8.314 kPa  L / mol K

T = 32 C = 273.15 + 32 = 305.15 K

n = moles = ?

Moles = PV / RT = 162.325 kPa X 5.2 / 305.15 X 8.314 = 0.332 moles

A 5.2 L-soccer ball with a gauge pressure of 61 kPa at 32 °C contains 332 moles of air.

Larisa pumps up a soccer ball until it has a gauge pressure of 61 kilopascals. The total pressure (P) inside the ball is the sum of the gauge pressure and the atmospheric pressure.

The air temperature (T) is 32 °C. We will convert this value to Kelvin using the following expression.

The volume (V) of the ball is 5.2 L. We can calculate the moles (n) of air inside the ball using the ideal gas equation.

A 5.2 L-soccer ball with a gauge pressure of 61 kPa at 32 °C contains 332 moles of air.

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