Calculate the number of grams of co2 formed when 0.370 kg of fe2o3 reacts.

Answer;

= 305.911 g CO2

Explanation;

The equation for the reaction;

Fe2O3 + 3 CO → 2 Fe + 3 CO2

mole ratio;

3  mol CO2 are formed from 1 mole of Fe2O3

Moles of Fe2O3 = (370 g Fe2O3) / (159.6887 g Fe2O3/mol)

                           = 2.317 Moles

Moles of CO2

= 2.317 × (3 mol CO2 /1 mol Fe2O3) = 6.951 moles

Therefore;

= 6.951 moles × (44.00964 g CO2/mol) = 305.911 g CO2

=305.911 g CO2

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.