2s+3o2 -> 2so3 indicate whether s or o2 is the limiting reactant, 3mol s 4mol o, 3mol s 5mol o, 3mol s 3mol? elemental s reacts with o2 to form so3 according to the reaction 2s+3o2 > 2so3 for each of the given situations, indicate whether s or o2 is the limiting reactant.

Balanced chemical reaction: 2S + 3O₂ → 2SO₃.

1) Answer is: oxygen is limiting reactant.

n(S) = 3 mol; amount of sulfur.

n(O₂) = 4 mol; amount of oxygen.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 4 mol of oxygen.

2) Answer is: sulfur(S) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 5 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

n(S) : 5 mol = 2 : 3.

n(S) = 10 mol ÷ 3.

n(S) = 3.33 mol; there is only 3 mol of sulfur, so it is not enough.

3) Answer is: oxygen (O₂) is limiting reactant.

n(S) = 3 mol.

n(O₂) = 3 mol.

From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.

3 mol : n(O₂) = 2 : 3.

n(O₂) = (3 · 3 mol) ÷ 2.

n(O₂) = 4.5 mol; limiting reactant, because there is only 3 mol of oxygen.