Consider the equilibrium, n2(g) + 2o2(g) < > n2o4(g). calculate the equilibrium constant, kp if the equilibrium partial pressures are 0.431 atm for n2o4, 0.0867 atm for n2 and 0.00868 atm for o2 6.60 x 104 1.75 x 10-3 573 1.52 x 10-5

The reaction given is

N2(g) + 2O2(g) <> N2O4(g)

Kp of reaction will be

Kp = pN2O4 / pN2 X p^2O2

Given

pN2O4 = 0.431

pN2 = 0.0867

pO2 = 0.00868

Putting values

Kp = 0.431 / 0.0867 X (0.00868)^2 = 6.60 X 10^4

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