The freezing point of benzene c6h6 is 5.50°c at 1 atmosphere. a nonvolatile, nonelectrolyte that dissolves in benzene is tnt (trinitrotoluene). how many grams of tnt, c7h5n3o6 (227.1 g/mol), must be dissolved in 297.0 grams of benzene to reduce the freezing point by 0.500°c ?

The amount required in grams to reduce the freezing point by 0.500 degree Celsius will be 6.58 g.

Solution: equation to calculate depression in freezing point

given: = 0.500°C

=  for benzene is 5.12

m=?

y= TNT amount (in grams) required

now according to formula:

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be