Part c identify the general outer electron configuration for each group of elements shown in this periodic table outline. drag each label to the appropriate target.

From left to right:

1) Answer is: ns¹.

This is group 1 (alkaline metals).

For example, sodium (Na) is an element with atomic number 11 and it has one valence electron (3s¹) like all alkaline metals.

Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.

2) Answer is: ns²(n-1)d¹.

For example, scandium (Sc) is an element with atomic number 21.

Electron configuration of scandium atom: ₂₁Sc 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹.

3) Answer is: ns²(n-2)f⁷.

For example, europium (Eu) is an element with atomic number 63.

Electron configuration of europium atom: ₆₃Eu [Xe] 6s² 4f⁷.

4) Answer is: ns²(n-2)f¹⁴(n-1)d¹⁰np¹.

For example, thallium (Tl) is an element with atomic number 81.

Electron configuration of thallium atom: ₈₁Tl [Xe] 6s²4f¹⁴ 5d¹⁰ 6p1¹.

5) Answer is: ns²(n-1)d¹⁰np⁴.

For example, selenium (Se) is an element with atomic number 34.

Electronic configuration of selenium atom: ₃₄Se 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁴.

6) Answer is: ns²np⁶.

For example, neon (symbol: Ne) is an element (noble gas) with atomic number 10, which means it has 10 protons and 10 electrons.

Electron configuration of neon atom: ₁₀Ne 1s²2s²2p⁶.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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it takes on an electronical energy