Asample of the chiral molecule limonene is 62% enantiopure. what percentage of each enantiomer is present? what is the percent enantiomeric excess?

The mixture contains 62 % one isomer and 38 % the enantiomer.

Let’s say that the mixture contains 62 % of the (R)-isomer.

Then % (S) = 100 % -62 % = 38 %

ee = %  (R) - % (S) = 62 % -38 % = 24 %