Chemistry, 08.07.2019 03:30 Haleysaraya1

How many sulfur atoms are present in 25.6 g of al2(s2o3)3

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Answer from: eli761029

Given the mass of $Al_{2}(S_{2}O_{3})_{3}$ =25.6 g

The molar mass of $Al_{2}(S_{2}O_{3})_{3}$ =390.35g/mol

Converting mass of $Al_{2}(S_{2}O_{3})_{3}$ to moles:

$25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}$

Converting mol $Al_{2}(S_{2}O_{3})_{3}$ to mol S:

$0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS$

Converting mol S to atoms of S using Avogadro's number:

1 mol = $6.022*10^{23}atoms$

$0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms$

Answer from: masonbitterman2604

Sulfur is a chemical element with symbol S. It is found in the in the group 16. It has atomic number 16 and atomic mass as 32 units. In the compound $\text{Al}_2(\text{SO}_3)_3$ there are 2.37 x $10^{23}$ atoms of sulfur are present.

Given that,

Mass of $\text{Al}_2(\text{SO}_3)_3$ = 25.6 gMolar mass of $\text{Al}_2(\text{SO}_3)_3$ = 390.35 g/molAccording to the formula of number of moles:

$\begin{aligned}\text{n}&=\frac{\text{mass}}{\text{molar mass}}\end{aligned}$

Now, converting mass of $\text{Al}_2(\text{SO}_3)_3$ into moles, we get:

$\begin{aligned}\25.6\;\text{g}[\text{Al}_2(\text{S}_2\text{O}_3)]\times\frac{1\text{mol\;Al}_2\text{S}_2\text{O}_3}{390.35\;\text{g}\;\text{Al}_2(\text{S}_2\text{O}_3)}&=0.0656\;\text{mol}\;\text{Al}_2(\text{S}_2\text{O}_3)\end{aligned}$

Similarly, for sulphur:

$\begin{aligned}\0.0656\;\text{mol}\;[\text{Al}_2(\text{S}_2\text{O}_3)_3]\times\frac{6\;\text{mol\;S}}{1\;\text{mol}\;\text{Al}_2(\text{S}_2\text{O}_3)_3}&=0.3936\;\text{mol\;S}\end{aligned}$

From the Avogadro's number, we know that,

1 mole = 6.022 $\times 10^{23}$ atoms.

Now, 0.3936 moles of sulphur will have: $\begin{aligned}0.3936\;\text{mol\;S}\times\frac{6.022\times10^{23}\text{atoms\;S}}{1\;\text{mol\;S}}&=2.37\times10^{23}\;\text{S\;atoms}\end{aligned}$

Therefore, the number of atoms of sulphur in the compound $\text{Al}_2(\text{SO}_3)_3$ is 2.37 $\times 10^{23}$ .

To know more about number of moles, refer to the following link:

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Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.