What is the iron (iii) ion concentration in 0.4309 m iron (iii) sulfate solution? select one: a. 2.780 m b. 0.4309 m c. 0.8619 m d. 1.293 m

c. [Fe³⁺] = 0.8618 mol·L⁻¹.

              Fe₂(SO₄)₃(s) ⟶ 2Fe³⁺(aq)    +   3SO₄²⁻(aq)

I/mol:        0.4309                   0                    0

C/mol:     -0.4309          +2×0.4309       +3×0.4039

F/mol:       0                          0.8618              1.293

Each mole of iron(III) sulfate produces two moles of Fe³⁺.

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

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