The mass of a single gold atom is 3.27×10-22 grams. how many gold atoms would there be in 43.2 milligrams of gold?

There are 1.32 × 10²⁰ atoms in 43.2 mg of gold.

Step 1. Convert grams of Au to moles of Au

Moles of SF₆ = 0.0432 g Au × (1 mol Au/196.97 g Au) = 2.193 × 10⁻⁴ mol Au

Step 2. Convert moles of Au to atoms of Au.

Atoms of Au = 2.193 × 10⁻⁴ mol Au × (6.022 × 10²³ atoms Au /1 mol Au)

= 1.32 × 10²⁰ atoms Au

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i think? ?

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3