A4.700 l sample of gas is cooled from 71.0 °c to a temperature at which its volume is 3.300 l. what is this new temperature? assume no change in pressure of the gas.

initial condition : Vi = 4.700 L , Ti = 71.0ºC +273 => 344 K

final condition : Vf = 3.300 L , Tf = ?

Pressure is constant:

According to charle's law , volume is directly proportional to temperature at constant pressure !

Hence  Vi / Ti  = Vf / Tf

4.700 L / 344 K = 3.300 L / Tf

Tf =  3.300 L * 344 K / 4.700 L

Tf = 1135200 / 4.700

Tf = 241.53 K

Tf = 241.53 - 273

Tf = -31.47ºC

i believe the answer is three water molecules