How many moles are in 987 grams of ra(oh)2?

Answer : 3.79 moles are in 987 grams of .

Solution : Given,

Mass of = 987 g

Molar mass of = 260 g/mole

Now we have to calculate the moles of .

Formula used :

Now put all the given values in this formula, we get the moles.

Therefore, 3.79 moles are in 987 grams of .

ok whats the question if not i cannot you i need question and need a thing to answer

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o