What is the empirical formula of a compound composed of 30.5 g potassium (k) and 6.24 g oxygen (o)?

The empirical formula of the compound is K₂O.

Step 1. Calculate the moles of each element

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of K to O.

Moles of K = 30.5 g K × (1 mol K/(39.10 g K) = 0.7801 mol K

Moles of O = 6.24 g O × (1 mol O/16.00 g O) = 0.3900 mol O

Step 2. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 2.001:1 ≈ 2:1

Step 3: Write the empirical formula

EF = K₂O

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml