Suppose that 0.05 g of nahco3 reacts with 0.05 g of hci and the reaction bubbles due to the carbon dioxide being produced. if the substance produced are 0.04 g water and 0.03g of salt how many grams if carbon dioxide gas were produced

The balanced chemical equation for the given reaction:

NaHCO₃ + HCl --> NaCl + H₂O + CO₂

Given, mass of NaHCO₃ = 0.05 g

Molar mass of NaHCO₃ = 84.007 g/mol

Moles = mass/molar mass

Moles of NaHCO₃ = 0.05 g/84.007 g/mol

Moles of NaHCO₃ = 6.0 x 10⁻⁴

Given, mass of HCl = 0.05 g

Molar mass of HCl = 36.46 g/mol

Moles of HCl = 0.05 g/ 36.46 g/mol

Moles of HCl = 1.4 x 10⁻³

Since NaHCO3 has the least number of moles, it is the limiting reagent.

As per the balanced equation the molar ratio between NaHCO₃ : CO₂ is 1:1

Therefore, moles of CO₂ = 6.0 x 10⁻⁴

Molar mass of CO₂ = 44 g/mol

Mass = moles x molar mass

Mass of CO₂ =  6.0 x 10⁻⁴ mol x 44 g/mol = 0.0264 g

Mass of carbon dioxide gas produced = 0.0264 g

i just learnt this recently but i need to look through my notes again

the dependant variable is spilled water

the independent is the heat