What is the molarity of a solution containing 45.78gmgcl2 dissolved in 3.00l of solution?

The formula is M (molarity) = mol / liters

molarity = ?

mass = 45.78g of MgCl2

Volume = 3.00L

1/ Convert grams to mol by using the formula:  mol = mass / Molar mass

    a/ Molar mass of MgCl2:

          Mg = 1 x 24.30 = 24.30 g/mol

          Cl = 2 x 35.45 = 70.9 g/mol

    Add them together:

         24.30 g/mol + 70.9 g/mol = 95.2 g/mol

    b/ mol = mass / Molar mass

        mol = 45.78 g / 95.2 g/mol

        mol = 0.4808

        ==> 0.4808 mol of MgCl2

2/ M = ?

   mol = 0.4808 mol of MgCl2

   Volume = 3.00L

M = mol / liters

M = 0.4808 mol / 3.00 L

M = 0.16 mol/L

well in order to answer this question you have to provide more information < 3

the answer to this question is 3.