Amixture of f2, h2 and xe have mole fractions of 0.25, 0.65, and 0.10, respectively. what is the pressure of f2 if the total pressure of the mixture is 3.9 atm?

Answer : The pressure of is 0.975 atm.

Solution : Given,

Mole fraction of = 0.25

Mole fraction of = 0.65

Mole fraction of = 0.10

Total pressure of mixture = 3.9 atm

According to the Dalton's law of partial pressure, which tells that the partial pressure of a gas is directly proportional to the mole fraction of a gas.

where,

= partial pressure of a gas

= mole fraction of a gas

= total pressure of gas

Now we have to calculate the partial pressure of gas.

Put all the given values in above formula, we get

The partial pressure of is 0.975 atm.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally