An electrically neutral atom of oxygen has eight electrons. what other facts do you know for sure about this atom? 1.) there are eight neutrons in the nucleus 2.) there are eight protons 3.) there is a charge of +8 on an atom of beryllium 4.) there is a charge of -8 on an atom of beryllium

The correct options are:

1.) there are eight neutrons in the nucleus

2.) there are eight protons

Explanation:

Since, it is given that given atom of oxygen is electrically neutral and it contains 8 electrons. This also means that number of protons present in it will also be 8.

Hence, its atomic number that is, sum of only total number of protons present in the oxygen atom are also 8.

Whereas mass number or atomic mass is the sum of total number of both protons and neutrons present in an element.

For example, given atom has atomic number is 8.  And, it is known that atomic mass of O is 16 g/mol.

Therefore, number of neutrons present in it will be calculated as follows.

                    Mass number = no. of protons + no. of neutrons

                         16 = 8 + no. of neutrons

                    no. of neutrons = 16 - 8  

                                               = 8

Hence, we can conclude that in the given atom of oxygen there are 8 protons and 8 neutrons.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.