Esteban finds that a small bar of pure gold, with a density of 19.3 g/cm³, displaces 80 cm³ of water. he calculates that it's mass is 1,544 g. he then calculates that a smalller bar, with half the volume of the first bar, has a mass half a great. is he correct? explain your reasoning.

Answer : Yes, he is correct.

Solution : Given,

Density of pure gold =

The pure gold displaces of water that means the Volume of pure gold is equal to the volume of water displaces.

Volume of pure gold =

Now we have to calculate the Mass of pure gold.

Formula used :      

By rearranging the formula, we get the mass of pure gold.

So, The mass of pure gold is 1544 g.

Now we have to calculate the Mass of pure gold when the volume become half.

The density of pure gold remains same because density is an intensive property which means that no matter how much of the substance is present, its value remains same.

Volume of pure gold =      

So, we conclude that when the volume become half then the mass also half.

fe 55.85 g/mol and h2o 18.02 g/mol.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.