What is the enthalpy for reaction 1 reversed? reaction 1 reversed: co2→co + 12o2 express your answer numerically in kilojoules per mole?

+283.0 kJ·mol⁻¹

Explanation:

If reaction 1 reversed is

CO₂ ⟶ CO + ½O₂,

then reaction 1 is

CO + ½O₂ ⟶ CO₂

Reaction 1 is the combustion of carbon monoxide, for which

ΔH = -283.0 kJ·mol⁻¹.

∴ The enthalpy change for reaction 1 reversed is +283.0 kJ·mol⁻¹.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.