3.264g of zonic chloride and 1.468g of zinc metal how much zinc obtained? was all zinc possible from the recovery?

3.264 g of ZnCl2 is 0.02394 moles. From the formula for ZnCl2, this is also the moles of Zn you should have gotten.

Atomic mass of Zn = 1.565 g is the theoretical yield you should have gotten

percent recovery = 1.468 g / 1.565 g * 100

answer: your mm

explanation:

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm