View the diagram below describe what happened in the diagram. the molecules on both sides of the chemical reaction are the same, because they are both mixtures. bonds were broken on the reactants and new bonds were formed on the products. the molecules expanded and cooled. bonds were broken on the reactants and no new bonds were formed on the products.

Answer : The correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.

Explanation :

In the chemical reaction, some substances react together are called reactant and the substance are formed are called product.

During the chemical reaction, the atoms of reactants rearranged to make products. There are on atoms are added or taken away in the reaction. This is known as the conservation of atoms.

For example : carbon atom react with the oxygen to form carbon dioxide.

From the given diagram, we conclude that the arrangement of molecules are different on both side of the mixture of reaction.

On the reactant side, the red molecules bonded with red molecule and the black molecule with white molecules. On the other hand i.e product side, the red molecule bonded with black molecule and white molecule bonded with red molecules. The molecular arrangement are different on both side of the reaction mixture.

Therefore, the correct answer is the Bonds were broken on the reactants and new bonds were formed on the products.

the molecules move in straight line until they collide with each other or with the walls of the container. collisions are perfectly elastic; when two molecules collide, they change their directions and kinetic energies, but the total kinetic energy is conserved.

explanation:

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.