If you had a total sample of 35 candium- 15 m& mium, 12 skittlitium and 8 mpeanuttium. what is the relative abundance for each

Given:

Total Candium = 35

# of M&M = 15

# of Skittlitium = 12

# of Peanutttium = 8

To determine:

The relative abundance  for each

Explanation:

Relative abundance = amount of each item in the sample/Sample total

M&M = 15/35 = 0.429 (or) 42.9 %

Skittlitium = 12/35 = 0.343 (or) 43.3 %

Peanuttium = 8/35 = 0.229 (0r) 22.9%

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer