Calculate the ph of a solution that has a [oh−] of 2.6 × 10^−6 m. a. 8.4 b. 6.5 c. 7.7 d. 6.29

A. 8.4

Explanation:

[OH⁻] = 2.6 × 10⁻⁶               Take the negative log of each side

-log[OH⁻] = pOH = 5.59     Apply the pH/pOH relation

pH + pOH = 14.00               Insert the value of pOH

pH + 5.59 = 14.00               Subtract 5.59 from each side

pH = 14.00 -5.59 = 8.41

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explanation:

the ratio of the conjugate base to the acid required to attain the desired ph.