The gas in a balloon occupies 2.25 l at 298 k at what temperature will the balloon expand to 3.50 l

The temperature  that the balloon will  expand to 3.50 l is  463.56 K

calculation

by use of Charles law formula

that is  V1/T1 = V2/T2   where;

V1 = 2.25 l

T1= 298 k

V2= 3.50 l

T2=?

 make T2 the subject of the formula  T2 =(V2  xT1) /v1

T2= (3.50 l x 298 K)  /2.25 L  = 463.56 K

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