Agas that exerts a pressure of 2.15 atm in a container with a volume of 0.0900 l will exert a pressure of atm when transferred to a container with a volume of a 4.75 l

Given:

Initial pressure exerted by the gas P1 = 2.15 atm

Initial volume of the container V1 = 0.0900 L

Final volume of the new container V2 = 4.75 L

To determine:

Pressure P2 exerted by the gas in the new container

Explanation:

The ideal gas equation is given as-

PV = nRT

where n = moles of the gas

R = gas constant and T = temperature

Since the values of n, R, T do not change when the gas is transferred to the new container, we have the relation

PV = constant

or, P1V1 = P2V2

P2 = P1V1/V2 = 2.15 * 0.0900/4.75 = 0.041 atm

Ans: The pressure exerted by the gas in the new container is 0.041 atm

c. heat could easily travel through the molecules in the air and escape/enter the flask. removing the air slows down the heat transfer.  

i think   the answer is c hope i'm right