Thallium-201 has a half-life 73 hours. if 4.0 mg of thallium-201 disintegrates over a period of 5.0 °, how many milligrams of thallium-201 will remain?

Given:

Half life of Thallium-201 (T1/2)= 73 hrs

Initial amount of thallium (A₀) = 4.0 mg

Disintegration Time period (t) = 5.0 hrs

To determine:

Amount of thallium remaining, A

Explanation:

The radioactive half-life (T1/2) can be related to the amounts of the radio active element through the relation:

A =

A = 4.0 * = 3.815 mg

Ans: Amount of thallium-201 remaining is 3.815 mg

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

the answer is   c.) 1575 j.

explanation: