Why are saturated hydrocarbons generally less reactive than unsaturated hydrocarbons? a. atoms are not easily added to molecules with single bonds. b. atoms are not easily added to molecules with double bonds. c. saturated hydrocarbons have fewer carbon atoms than unsaturated hydrocarbons.

The correct answer is Option A.

Explanation:

Saturated hydrocarbons are defined as the hydrocarbons in which single bond is present between C-C atoms. The general formula used for these hydrocarbons is

Unsaturated hydrocarbons are defined as the hydrocarbons which have double or triple covalent bonds present between carbon and carbon atoms. They are known as alkenes and alkynes respectively. The general formula used for these hydrocarbons is and

Unsaturated hydrocarbons are more reactive than the saturated ones because of the presence of bonds. They are weaker than bonds and thus can be easily broken. Addition reactions is more favorable for the compounds having bonds.

Saturated hydrocarbons have only bonds and thus are strong bonds and cannot undergo addition reaction easily.

Thus, the correct answer is Option A.

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the   per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:                   1 - α               α               α           = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

=  

or,

or,   = (at v = 1l)

the reaction:                     so₂cl₂ (g) = so₂ (g) + cl₂ (g)         total

the moles at equilibrium:   1 - α                 α               α           = 1+α

concentrations:               (1 - α)/0.5           α/0.5         α/0.5       = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

or,  

=  

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

i'm assuming that it's c.) red bank..