What is the correct unabbreviated electron configuration of the following? : vanadium: strontium: carbon:

The correct  unabbreviated electron configuration  is as below

Vanadium - 1S2 2S2 2P6 3S2 3p6 3d3 4s2

Strontium -  1s2 2S2 2P6 3S2 3P6 3d10 4S2 4P6 4S2

Carbon =1S2 2S2 2P2

Explanation

vanadium  is in atomic number  23  in the periodic table  hence its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d3 4s2

Strontium is in atomic number 38  in periodic table  hence  its electron configuration is 1s2 2s2 2p6 3s2 3p6 3d10  4s2 4p6 4s2

Carbon is in atomic number 6 in periodic  table  therefore its electron configuration is 1s2 2s2 2p2

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)