What volume in l of a 0.32 m mg(no3)2 solution contains 45 g of mg(no3)2?

0.94L

Explanation:

As a solution of concentration of 0.32 M indicates that contains 0.32 moles of the compound in 1L of solution. So we need to calculate the grams of Mg(NO3)2 in 0.32 M:

×

This is telling you that you have 47.5 g de Mg(NO3)2 per liter of solution.

Now, using a rule of three you can know de volume that occupies a solution containing 45 g of Mg(NO3)2:

47.5 g Mg(NO3)2 → 1L solution

45 g Mg(NO3)2 → x

Finally, we have 45g of Mg(NO3)2 in a volume of 0.94L of solution 0.32 M Mg(NO3)2.