How many molecules of o2 are present in a 3.90l flask at a temperature of 273k and a pressure of 1.00atm?

Hello!

How many molecules of O2 are present in a 3.90L flask at a temperature of 273K and a pressure of 1.00atm?

We have the following data:

V (volume) = 3.90 L

n (number of mols) = ?

T (temperature) = 273 K

P (pressure) = 1 atm

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

Now, knowing that by Avogadro's Law for each mole of a substance we have 6.022 * 10²³ molecules, how many molecules of O2 are present ?

1 mol -------------------- 6.022*10²³ molecules

0.174 mol ---------------- y molecules

multiply the means by the extremes

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I Hope this helps, greetings ... Dexteright02! =)

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%