Which of the following statements is true about the strength of the intermolecular forces in ch4 and nh3? a: ch4 ≥ nh3 because ch4 is tetrahedral but nh3 is pyramidal. b: ch4 < nh3 because δ− on c in the ch bond is greater than δ− on n in the nh bond. c: ch4 < nh3 because the nh bond is more polar than the ch bond. d: ch4 ≥ nh3 because ch4 has h bonding but nh3 has dispersion forces.

C: CH4 < NH3 because the NH bond is more polar than the CH bond.

- C) because the NH bond is more polar than CH bond.

Explanations:- methane is tetrahedral and it is symmetrical as all the bonds are same. Also, the electron negativity difference of C and H is too low and the molecule is almost non polar and makes the methane to have London dispersion forces.

Ammonia is trigonal pyramidal due to the presence of lone pair of electrons on central nitrogen atom. Nitrogen is highly electron negative atom so the N-H bond is more polar. Also, hydrogen bonding is possible in ammonia as the hydrogen is bonded to more electron negative nitrogen atom.

First option is not correct as the inter molecular forces are weaker in methane as compared to ammonia. Methane has only London dispersion forces where as ammonia has dipole-dipole as well as hydrogen bonding.

Second option is also not correct because the carbon has less partial negative charge as compared to N due to less electron negativity difference of C and H atoms.

Last choice is also not correct since the hydrogen bonding is not present in methane.

So, the only and only correct choice is C) because the NH bond is more polar than CH bond.

most historians agree that gabriel mouton, the vicar of st. paul’s church in lyons, france, is the “founding father” of the metric system. he proposed a decimal system of measurement in 1670. mouton based it on the length of one minute of arc of a great circle of the earth (now called a nautical mile, 1852 meters). he also proposed the swing-length of a pendulum with a frequency of one beat per second as the unit of length (about 25 cm). a pendulum beating with this length would have been fairly easy to produce, thus facilitating the widespread distribution of uniform standards. over the years, his work was revised, improved, and extended by a number of french scientists.

the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).

i wish i could but this one is weird give me abc and i can solve it.