Calculate the molarity of each type of ion remaining in solution after 20.0 ml of 6.00 m hcl is mixed with 50.0 ml of 2.00 m barium hydroxide and 30.0 ml of water.

Answer : The molarity of each type of ion remaining in solution are :

Molarity of ions = 0.8 mole/L

Molarity of ions = 1.2 mole/L

Molarity of ions = 1 mole/L

Explanation:

The given reaction is,

= 0.12

As 1 mole of HCl dissociates to give 1 mole of and 1 mole of  

So, 0.12 mole of HCl dissociates to give 0.12 mole of and 0.12  

= 0.1

As 1 mole of dissociates to give 2 moles of ions,  

So, 0.1 moles of dissociates to give 0.1 moles of and 0.2 moles of  

As 0.12 mole of ions will neutralize 0.12 moles of ions.

So, remaining ions in the solution will be 0.2 - 0.12 = 0.08 moles

So, moles of ions after the reaction = 0.08 moles

Now we have to calculate the molarity of each type of ions remaining in solution.

Total volume = 20 + 30 + 50 = 100 ml

Molarity of ions =

Molarity of ions =

Molarity of ions =

explanation:

detials on each model with digrams

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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