If 3.85 moles of aluminum (al) metal, with a density of 2.70 g/ml, are needed for a chemical reaction, how many milliliters of aluminum are needed?

select one:
a. 1.43 ml al
b. 18.9 ml al
c. 38.5 ml al
d. 281 ml al

To find mL of Al needed, start by finding grams of Al that are being used in this reaction:
(3.85mol Al)(27.0g/mol Al)= 104g Al needed.

Since density is m/v, and we know the density and the mass, we can find the volume:
2.70g/mL = (104.g)/mL
Isolate mL:
(104.g)/(2.70g/mL) = 38.5mL needed which is answer C :)