An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. what amount of force would be required to keep the object in motion if you ignore the sureface friction?

F = MA A = change in velocity Constant velocity = no change in velocity = Zero acceleration Ignoring friction, 5 kg * 0 m/s^2 = 0 N Therefore, there is no force (0 N) required to keep the object in motion if the surface friction is ignored.

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

it is a good conductor

explanation: