N2(g) effuses at a rate that is times that of kr(g) under the same conditions.

- gas effuses at a rate that is 1.73 times that of Kr gas under the same conditions.

Solution:- Rate of effusion of gases is inversely proportional to the square root of the molar mass of the gas. It is known as Graham's law. The formula is written as:

Since we have nitrogen and krypton gases, so let's write the formula as:

where r stands for rate of effusion and M stands for molar mass.

Molar mass of nitrogen gas is 28.01 gram per mol and the molar mass of krypton gas is 83.8 gram per mol.

let's plug in the values in the formula:

= 1.73

So, the rate of effusion of nitrogen gas is 1.73 times that of Kr.

oh it is true if thats what you are asking

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.