How many kj of heat are needed to completely vaporize 3.30 moles of h2o? the heat of vaporization for water at the boiling point is?

The heat of vaporization for water at the boiling point is 40.6 kJ/mole

Q = ( moles of water ) ( molar latent enthalpy of water or heat  of vaporization of water )  

Q = 3.30 moles X 40.6 kJ/mole = 134 kJ

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.