You are balancing an ionic compound. let's call it: ab. ion a has a charge of +2 and ion b has a charge of -3. therefore, you determine that the ionic compound (ab) will have a ratio of 3 as for every 2 bs. how would you modify ab in order to show that they have this 3-to-2 ratio? question 2 options: 3a2b a3b2 a3b2

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Explanations:- It is given that the charge for A is +2 and the charge for B is -3. The over all compound is neutral means the over all charge is zero. For making the over all charge zero, we need 3 positive ions and 2 negative ions. This makes a +6 charge for A and -6 charge for B and the over all charge is zero.

Also, if we think about the criss cross then charge of A becomes the subscript of B and the charge of B becomes the subscript of A.

So, the formula of the ionic compound is . In this compound the ratio of A to B is 3:2.

The balanced equation could be shown as:

2b2t

explanation:

2b2t

what is the average time it took the car to travel 0.25 meters?

⇒ 2.23 seconds

what is the average time it took the car to travel 0.50 meters?

⇒ 3.13 seconds