What mass of hcl, in grams, is required to react with 0.610 g of al(oh)3  ?

0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

Given mass of = 0.610 g

Molar mass of = 78 g/mol

Number of moles of = 0.0078 moles

The reaction between and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

By Stoichiometry,

1 mole of   reacts with 3 moles of HCl

So, 0.0078 moles of will react with = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

Mass of HCl required will be = 0.8541 grams