Pd-100 has a half life of 3.6 days. if one had 6.02 x 10 to the 23 atoms at the start, how many atoms at the start, how many atoms would be present after 20 days?

1.28 × 10²² atoms of Pd-100 would be present after 20 days.

To calculate the amount of atoms present after a half-life decomposition process, it is necessary to use the following formula:

Since the initial amount of mass is equal to atoms, the half-life is 3.6 days and the total time is 20 days, we just have to put these values in the expression above:

                                            atoms

So, after 20 days there will be atoms of Pd-100.

Learn more about half-life in: link

1.28 × 10²² atoms

Step-by-step explanation:

A common formula for determining the amount of sample remaining (N) in terms of its half-life (t_½) is

N =N₀(½)ⁿ

where n is the number of half-lives

n = t/t_½

Data:

N₀ = 6.02 × 10²³ atoms

t = 20 da

t_½ = 3.6 da

The calculation:

N₀ =6.02 × 10²³ atoms

n = 20/3.6

n= 5.56

N = 6.02 × 10²³ × (½)^5.56

N = 6.02 × 10²³ × 0.0212

N = 1.28 × 10²² atoms

the tides are influenced by both the moon and the sun, it's easy to see that when the sun lines up with the moon and the earth, as during a new moon or full moon, the tidal effect is increased. these are known as spring tides, named not for the season, but for the fact that the water "springs" higher than normal. on the other hand, if the sun and the moon are 90 degrees apart in relation to an observer on earth as during the first quarter moon or third quarter moon, then high tides are not as high as they normally would be. this is because despite its greater distance, the sun's mass allows it to exert enough gravitational force on the oceans that it can negate some of the effects of the moon's pull. this phenomenon of lower high tides is called a neap tide. if you need more information on this topic visit moonconnection.com.