If you add 4.00 ml of pure water to 6.00 ml of 0.750 m nacl solution, what is the concentration of sodium chloride in the diluted solution?

Given:

Initial volume of water V1 = 6.00 ml

Initial concentration of NaCl M1 = 0.750 M

Volume of water added = 4.00 ml

To determine:

The final concentration M2 of NaCl

Explanation:

The final volume V2 = 6.00 + 4.00 = 10.0 ml

Use the relation:

M1V1 = M2V2

M2 = M1V1/V2 = 0.750*6.00/10.0 = 0.450 M

Ans: The concentration fo diluted NaCl = 0.450 M

wher is the rest of the question

i think its 100.

hope this !