Identify the compound with the smallest percent ionic character. identify the compound with the smallest percent ionic character. hf lif ibr hcl

IBr has the smallest percentage ionic character amongst the given compounds.

Explanation: Percentage ionic character is calculated by using the formula:

   ....(1)

where, = difference in the electronegativies of the element forming a compound.

Electronegativity of H = 2.1

Electronegativity of F = 3.98

Electronegativity of Li = 0.98

Electronegativity of I = 2.66

Electronegativity of Br = 2.96

Electronegativity of Cl = 3.16

Putting this in equation 1, we get:

Putting this in equation 1, we get:

Putting this in equation 1, we get:

Putting this in equation 1, we get:

From the above calculations, we see that IBr has the smallest percent ionic character.

2b2t

explanation:

2b2t