Calculate the concentration (m) of sodium ions in a solution made by diluting 80.0 ml of a 0.174 m solution of sodium sulfide to a total volume of 125 ml.

 The concentration   of sodium  ion   is  0.2228 M

      calculation

find the molarity  of  Na₂S  solution using M₁V₁=M₂V₂  formula

where M₁ = 80.0 ml

          V₁= 0.174 M

         M₂ = ?

         V₂ = 125 ml

make  M₂  the subject   of   the formula   by  diving both side by V₂

M₂= M₁V₁/V₂

M₂ = [ (80.0 ml  x 0.174 M) / 125 ml]= 0.1114 M

write the  equation for dissociation  of Na₂S

Na₂S→ 2Na⁺(aq)   + s²⁻ (aq)

from equation above the  mole  ratio  of  Na₂s : Na⁺  is 1:2 therefore the concentration  of

Na⁺= 0.1114 x 2 =0.2228 M

for points guys

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current