Match the reaction on the right with the corresponding reaction on the left by writing the correct, matching number in the space provided. solid sodium + chlorine gas → solid sodium chloride solid sodium + liquid water → aqueous sodium hydroxide + hydrogen gas 2h2(g) + o2(g) → 2h2o(g) 2h2o2(aq) → o2(g) + 2h2o(l) 1) aqueous hydrogen peroxide → oxygen gas + liquid water 2) 2na(s) + cl2(g) → 2nacl(s) 3) hydrogen gas + oxygen gas → water gas 4) 2na(s) + 2h2o(l) → 2naoh(aq) + h2(g)

Explanation:

The first given equation in words is as follows.

solid sodium + chlorine gas solid sodium chloride

The chemical equation for this reaction will be written as follows.

The second given equation in words is as follows.

solid sodium + liquid water aqueous sodium hydroxide + hydrogen gas

The chemical equation for this reaction will be written as follows.

The third given equation is as follows.

This equation can be written in words as follows.

hydrogen gas + oxygen gas water gas

The fourth given equation is as follows.

This equation can be written in words as follows.

aqueous hydrogen peroxide oxygen gas + liquid water

Thus, match the given data as follows.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.