Given the following reaction: 3feo + 2cu3n --> fe3n2 + 3cu2o how many moles of copper (i) nitride are needed to form 35.7 grams of copper (i) oxide? question options: .213 .166 .198 .312

(Answer) 0.166 moles of copper (I) nitride are needed.

Mass of copper (I) oxide = 35.7 g

Moles of copper (I) oxide formed by the reaction = (Mass / molar mass)

= ( 35.7 g / 143.09 g/mol ) = 0.25 moles

According to the balanced chemical equation,

mole ratio of copper (I) nitride and copper (I) oxide = 2: 3

Therefore, moles of copper (I) nitride needed to form 0.25 moles of copper (I) oxide = (2/3 x 0.25) moles = 0.166 moles.

Thus, 0.166 moles of copper (I) nitride are needed to form 0.25 moles of copper (I) oxide.

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