You have 4.872 x 1034 atoms of copper. how many moles is this? 7.666 x 10^32 mol 2.933 x 10^58 mol 1.237 mol 8.093 x 10^10 mol

The answer is 8.093*10^10 mol.

To solve the question, just plug in the information into this equation:

n = N/NA

Where:

n - number of moles

N - number of atoms

NA - avogadro's number (6.022*10^23)

We know the number of atoms, as well as NA. Divide for the number of moles.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l